Suppose you want to know the local maximums and minimums of the following function:
\[ f(x) = 2x^3 - 9x^2 + 12x - 3 \]
The result should be x = 1 and y = 2 (it is displayed next to the point). You can apply the same procedure to find a local minimum by pressing select Analyze Graph > Minimum instead of select Analyze Graph > Maximum.
This strategy is useful when one one only wants the y values of the global maximum or minimum. If you have to know the x values too, see above.
Suppose you want to find the maximum and minimum of the following function:
\[ f(x) = x^3 - x + 1, \quad -1 \leq x \leq 1. \]
Thus, the minimum of f is 0.538, and the maximum is 1.462. Thus, the range of f is
\[ 0.538 \leq y \leq 1.462. \]
Suppose you want to know the local maximums and minimums of the following function:
\[ f(x) = 2x^3 - 9x^2 + 12x - 3 \]
Recall that we want to compute f (0).
The result Y=-3 should be displayed within the coordinate of the point (at the bottom right of the screen).
Suppose you want to know the local maximums and minimums of the following function:
\[ f(x) = 2x^3 - 9x^2 + 12x - 3 \]
Recall that we want to compute the value of x when f(x)=0
The result X=0.322 should be displayed within the coordinate of the point.
\[ \frac{2x^3 - 4x + 2}{5x^3 - x^2 + 2} \]
The result should be Y=0.4 (rounded).
\[ \frac{2x^3 - 4x + 2}{5x^3 - x^2 + 2} \]
The result should be x = 0.676 (rounded).
Depending on how precise you want the result to be, you will have to zoom in more, and move again the cursor
\[ f(x) = x^2 - 2x + 2, \quad g(x) = \frac{x + 10}{4}. \]
Press . The intersection points should be (-0.204,2.45) (left intersection point) and (2.45,3.11) (right intersection point) (rounded).